Open Science Repository Mathematics
doi: 10.7392/Mathematics.70081937
A Demonstration of the Fermat's Theorem
Mitko Donev
Stara Zagora, Bulgaria
Abstract
This demonstration rests on the premise that the equation admits at least one valid solution for any triple of positive integers raised to the power n, where n > 2.
Keywords: mathematics, Fermat theorem, demonstration.
Citation: Donev, M. (2013). A Demonstration of the Fermat’s Theorem. Open Science Repository Mathematics, Online(open-access), e70081937. doi:10.7392/Mathematics.70081937
Received: February 7, 2013
Published: March 8, 2013
Copyright: © 2013 Donev, M. Creative Commons Attribution 3.0 Unported License.
Contact: [email protected]
Full Text
The equation
has not determination for positive integers with

degree when

.
The argument of this
demonstration assumes that the equation possesses at
least one valid solution for any triple of positive integers
raised to the power

when

.
For this
demonstration of the theorem, I rely on the only proven equation
of this type, namely the Diophantine equation

,
known in mathematics as the Pythagorean Theorem. For notation, I
will build a matrix of numbers with

columns and
rows,
where the column numbers indicate the number in the rows below raised to
the power equal to the row number of the matrix.
The matrix is
shown in this form:
Numbers
and columns
|
1
|
2
|
3
|
4
|
5
|
n
|
|
Rows
and powers
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1
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2
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3
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4
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n-2
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n-1
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n
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n+∞
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I replace the
numbers from the rows and columns with a generated number C
nn,
where the index nn indicates the row number and column number
when it is an integer.
The matrix then
appears as follows:
Numbers
and columns
|
1
|
2
|
3
|
4
|
5
|
n
|
n+∞
|
Rows
and powers
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1
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2
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3
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4
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n-2
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n-1
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n
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n+∞
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I express the power
of
Cnn
as the sum of powers of a pair of numbers
a,
b,
or write this equation in a general form:
Сnnn
= ann
n
+ bnn
n
I stress then
that
ann
n
+ bnn
n
stands for
all possible pairs of numbers satisfying the
above equation for every possible
Cnn
from the matrix. I add a clarification to avoid the misunderstanding
that both numbers are the same for all
Cnn.
I do this for convenience and to avoid writing countless
characters, which could lead to confusion and misunderstanding of the
thesis.
I set out the order of
all possible equations in the matrix.
Numbers
and columns
|
1
|
2
|
n
|
n+∞
|
Rows
and powers
|
|
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1
|
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2
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3
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4
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n-2
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n-1
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n
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n+∞
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=
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=
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=
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=
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I also want to
clarify that the possible solutions include cases where the
values (taken separately) of

are
rational or negative numbers.
Here is an example taking the number
from column 42, row 3, where:
I
express it as the sum of this power of numbers
From this solution it is seen that
Here b is a
negative number, and the third root of their sum is exactly 42.
Let, in the matrix
described above, the row and columns

summarize equations in all cases of such solutions. These solutions satisfy
the thesis of the theorem and are not of interest to the
demonstration. They meet the condition that the equation
has no solutions for positive integers.
Let the (n-th) row and column of the
matrix summarize all possible cases for solving the equations, when
the numbers a, b, c and their power n are positive integers.
The demonstration
will rest on the assumption of the opposite claim, that the
equation has a solution for positive integers. It is notable that I do not
mention limits on the range of the power. This is intentional and I
will use it in the demonstration. I will determine all possible solutions
of the equation over the range of the power n from 1 to plus
infinity.
For this I will use the only proven equation to
date, which is at second power, known as the
Pythagorean Theorem.
It is interesting that the Pythagorean
Theorem has solutions for n pairs of positive integers that result
from the first three numbers as follows:
3
|
4
|
5
|
6
|
8
|
10
|
12
|
16
|
20
|
…….
|
…….
|
…….
|
N*2
|
N*2
|
N*2
|
Each successive row
results from the previous one when its numbers are doubled, and they satisfy
the equality. There are countless solutions of the theorem when the
numbers are rational or not positive integers.
Since the scope of the assertion of
Fermat’s theorem excludes the second power of the equation
I consider the theorem of Pythagoras over
its full range of solutions for whole and rational numbers. I will
carry out the demonstration column by column, considering all possible
cases.
I begin with column 1, equal to one;
the equations in the column can be solved as a system of equations.
I assume that in the entire column there is at least one true equation
As proven by
Pythagoras in the second row of the matrix:
Solving a system of the two true
equations, I deduce C from them

;

;
Equating both sides, and therefore
To simplify the equation, set the two sides
as follows
The result is the equation below:
Using logarithms, find
the power R of T to which it must be raised to obtain K
Substituting K, the result is the
following equation
Hence the
solutions of the equation depend on the solution of this equation:
Hence the solutions of the equations
depend on the solution of the following equation
R=2/n
The solutions of the
equation

for n (1,2,3,4………..

) is:
…………..

or
For the equation to
be true
And,
if there are countless solves for positive integers, than
in the interval for its
It
is necessary to discover the countless positive integers, but because
of the range consists of fractions of which the dividend is the
number 2, the only positive whole numbers are 1 and 2. This holds
because
the number 2 is prime and divisible only by 1 and
itself, from which it follows that
n
is a positive integer only when R = 1 or 2.
Therefore,
the system can be solved only when R = 1 or 2 for the assertion that the equation has solutions for positive whole
numbers to hold.
Analogously,
constructing systems for each row of the matrix and performing the same
proof leads to the same conclusion.

;
The
result is that n is a positive integer only when R equals R=1 or
R=2.
Therefore,
constructing similar systems for each row of the matrix and performing the
same proof leads to the same conclusion.
I find n in the equation, where n equals
2 divided by R
The solutions of the equations from the
first column
Numbers
and columns
|
1
|
Rows
and powers
|
|
1
|
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2
|
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3
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4
|
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n-2
|
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n-1
|
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n
|
|
Depending on the solution
of the equation

for n in the range (1; 2; 3;……….

)
For n in the range
(1; 2; 3;……….

)
all possible equations are:
|
n=
|
Where
R=1
|
Where
R=2
|
powers
|
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n=
|
n=
|
1
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2
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3
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4
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……
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…………
|
………..
|
……….
|
n
|
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Where R=1 and R=2
Therefore the solutions of
the equation

for a positive integer n are two.
I substitute

;
Where R=1 and R=2.
The only possible solutions for the equalities
from the first column are

;
According to
Fermat’s theorem, these equalities are excluded from the scope of
the interval for n>2 set by the task condition, with which I
demonstrate the assertion that the other equalities have no solutions for
positive integers.
The same method is used to
demonstrate the result for all other columns of the matrix.
Connections
1. Alladi, K. (2013). Fermat and Ramanujan: A Comparison. In Ramanujan's Place in the World of Mathematics (pp. 27-30). Springer India.
2. Darmon, H., Diamond, F., & Taylor, R. (1995). Fermat’s last theorem. Current developments in mathematics, 1, 1-154.
3. Wiles, A. (1995). Modular elliptic curves and Fermat's last theorem. Annals of Mathematics, 443-551.
4. Stewart, I., & Tall, D. O. (2002). Algebraic number theory and Fermat's last theorem. AK Peters.
5. Kleiner, I. (2012). Fermat’s Last Theorem: From Fermat to Wiles. Excursions in the History of Mathematics, 47-64.
Cite this paper
APA
Donev, M. (2013). A Demonstration of the Fermat’s Theorem. Open Science Repository Mathematics, Online(open-access), e70081937. doi:10.7392/Mathematics.70081937
MLA
Donev, Mitko. “A Demonstration of the Fermat’s Theorem.” Open Science Repository Mathematics Online.open-access (2013): e70081937. Web. 8 Mar. 2013.
Chicago
Donev, Mitko. “A Demonstration of the Fermat’s Theorem.” Open Science Repository Mathematics Online, no. open-access (March 8, 2013): e70081937. http://www.open-science-repository.com/a-demonstration-of-the-fermats-theorem.html.
Harvard
Donev, M., 2013. A Demonstration of the Fermat’s Theorem. Open Science Repository Mathematics, Online(open-access), p.e70081937. Available at: http://www.open-science-repository.com/a-demonstration-of-the-fermats-theorem.html.
Science
1. M. Donev, A Demonstration of the Fermat’s Theorem, Open Science Repository Mathematics Online, e70081937 (2013).
Nature
1. Donev, M. A Demonstration of the Fermat’s Theorem. Open Science Repository Mathematics Online, e70081937 (2013).
doi
Research registered in the DOI resolution system as: 10.7392/Mathematics.70081937.

This work is licensed under a Creative Commons Attribution 3.0 Unported License.